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#1
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2350 RPM gives me about 150 - 154 true
I like this setting because my engines seem to just feel better and are smooth If I'm in a hurry though it's 24-2500 RPM and about 158 - 160 true Fuel burn, 18 vs 21
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Herb R Harney 1968 337C Flying the same Skymaster for 47 years |
#2
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Its all in the curves
The weight of the airplane is 'constant' (at any instant)
That weight W requires an equal amount of lift L to stay aloft To produce that lift induces a certain amount of drag D The most efficient flight is in thin air when lift L is 'just enough' to hold the airplane up, and drag is least (the 'coffin corner' for jets. Efficient but scary). As throttle opens, airflow becomes more 'laminar' So at max throttle engine breathes most air/fuel with least disturbance As one climbs the engine as an air pump cant get enough air So for fuel/air to remain stochiometric, reduce fuel to match less air As throttle opens, airflow becomes more 'laminar' So at max throttle, engine breathes most air/fuel with least disturbance That's why most non-turbo cruise best around 7-9k feet Throttle is full open but still getting enough air for available fuel flow Adding more fuel wont add more power from burn, just richen mixture Fly higher up and fuel must be reduced to available 02, so HP output drops off Except for turbo. But even turbo increases internal combustion 'drag' (energy to spin the turbo is not free). Most efficient wing moves a lot of air just a little bit A 'flat' blade at low RPM moves a lot of air a little distance per rotation So prop efficiency better 'flat' as in takeoff But delta V across blades (front to back) a function of cruise speed The idea is to 'paddle' the air with least disturbance And of course, internal engine friction a function of RPM Turn the engine two times and it that produces two times the friction per unit of time. If you can solve all those, you get an 'A.' -- The only lower limit consideration I have read has to do with the internal harmonic balancing of the engine. Spin too slow and harmonics increase vibration in some manner. Which of course consumes energy as heat, not output. E=MC^2 F=Mass x Acceleration K=1/2 Mass *Velocity ^2 Those aren't just good ideas, they are the law.
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David Wartofsky Potomac Airfield 10300 Glen Way Fort Washington, MD 20744 |